Print unknown_str in case of error

func can return NULL in case of error, but no checking is done when
printing, and unknown_str wasn't being used anywhere.

diff --git a/slstatus.c b/slstatus.c
index 89a3268697f6dab16a55266237ab040828306049..19bc127f54b95ff5bc22f51d4f1d8fef683a73b7 100644 (file)
--- a/slstatus.c
+++ b/slstatus.c
@@ -87,8 +87,10 @@ main(int argc, char *argv[])
 
                status[0] = '\0';
                for (i = len = 0; i < LEN(args); i++) {
+                       const char * res = args[i].func(args[i].args);
+                       res = (res == NULL) ? unknown_str : res;
                        len += snprintf(status + len, sizeof(status) - len,
-                                       args[i].fmt, args[i].func(args[i].args));
+                                       args[i].fmt, res);
 
                        if (len >= sizeof(status)) {
                                status[sizeof(status) - 1] = '\0';